HT Media Ltd.
Time : 2- 3 hrs
Type : Online
IDE can be used.
Tips : Write at least partial code for the problem statement, they consider it and ask the code what you have written in the Interviews(if you are shortlisted). Mostly None could write complete code in our batch.
PROBLEM STATEMENT:
Calculator Language (CL) supports assignment, positive and negative integers and simple
arithmetic. The allowable characters in a CL statement are thus:
A..Z : Variables
0..9 : Digits
+ : Addition operator
- : Subtraction operator
* : multiplication operator
/ : integer division operator
= : assignment operator
() : brackets
- : negative sign
All operators have the same precedence and are right associative, thus 15 - 8 - 3 = 15 - (8 - 3) = 10.
As one would expect, brackets will force the expression within them to be evaluated first. Brackets
may be nested arbitrarily deeply. An expression never has two operators next to each other (even if
separated by a bracket), an assignment operator is always immediately preceded by a variable and
the leftmost operator on a line is always an assignment. For readability, spaces may be freely
inserted into an expression, except between a negative sign and a number. A negative sign will not
appear before a variable. All variables are initialised to zero (0) and retain their values until changed
explicitly.
Write a program that will accept and evaluate expressions written in this language. Each expression
occupies one line and contains at least one assignment operator, and maybe more.
Input :
Input will consist of a series of lines, each line containing a correct CL expression. No line will be
longer than 100 characters. The file will be terminated by a line consisting of a single #.
Output :
Output will consist of a series of lines, one for each line of the input. Each line will consist of a list
of the final values of all variables whose value changes as a result of the evaluation of that
expression. If more than one variable changes value, they should be listed in alphabetical order,
separated by commas. If a variable changes value more than once in an expression, only the final
value is output. A variable is said to change value if its value after the expression has been evaluated
is different from its value before the expression was evaluated. If no variables change value, then
print the message `No Change'. Follow the format shown below exactly.Sample input
A=B=4
C = (D = 2)*_2
C = D = 2 * _2
F=C-D
E = D * _10
Z = 10 / 3
#
Sample output
A = 4, B = 4
C = -4, D = 2
D = -4
No Change
E = 40
Z=3
